How many three person committees can be chosen from a group of eight people?
this is a combination problem
the formula for # of combinations of r objects chosen from n
= nCr = n! / (r! * (n-r)!) where, say n! is read as factorial n & = n(n-1)(n-2)….1
8C3
= 8! / (3! * 5!)
= 8*7*6/(3*2*1)
= 56
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